(1/1-y)+(2/y^2-1)

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Solution for (1/1-y)+(2/y^2-1) equation: 


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

2/(y^2)-y+1/1-1 = 0

2/(y^2)-y-1+1 = 0

2*y^-2-y = 0

y*(2*y^-3-1) = 0

2*y^-3 = 1 // : 2

y^-3 = 1/2

-3 < 0

1/(y^3) = 1/2 // * y^3

1 = 1/2*y^3 // : 1/2

2 = y^3

y^3 = 2 // ^ 1/3

y = 2^(1/3)

y = 0

y = 0

y in { 0} 

y = 2^(1/3)

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